# Can you please assist with the question below: Create a new function named max which accepts two numbers as arguments (y

Create a new function named max which accepts two numbers as arguments (you can name the arguments, whatever you would l

script.js
```var

function max(arg1, arg2) {
return large;
}
if
``` Hey Josephine,

```function max(num1, num2) { // num1 && num2 are our arguments
// Next we need to figure out what number is greater, num1 or num2. In this case we are passing 12 = num1 and 3 = num2..
if(num1 > num2) {  // So if num1 is greater, which it is in this case.
return num1; // We then return num1
} else {
return num2;
}
}
console.log(max(12, 3));
```

Another case if num2 happened to be our greater number.

```function max(num1, num2) { // num1 && num2 are our arguments
// Next we need to figure out what number is greater, num1 or num2. In this case we are passing 1 = num1 and 31 = num2..
if(num1 > num2) {  // So if num1 is greater, which now it's NOT && ='s( equals ) false.
return num1;
} else {
return num2; // We then return num2
}
}
console.log(max(1, 31));
```

Hopefully this helps you out. Let me know if you need further help, thanks.

Thank you soo much.. It has really helped

function max(a, b) { if (a > b) { return a; } else { return b; } } function max(10, 50) { if (10 > 50) {
return 10; } else { return 50; } }

/* function max(a, b) { if (a > b) { return a; } else { return b; } } */

I'm sorry, I'm doing accordin this example; but it does not work for me, Could assist me you this please

function max(a,b) { if (a > b) { return("first is greater"); } else { return("second is greater"); }

max(4,5);

its saying the 'max' function isn't returning a number. How do i correct that error?