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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Abhinav Das
Abhinav Das
1,729 Points

Cannot debug Error

seems to give correct output as per my understanding and the test cases I ran

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(input):
    words = input.lower().split(" ")
    ma = {}
    for word in words:
        if(word in ma.keys()):
            ma[word] +=1
        else:
            ma.update({word : 1})
    return ma

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

The code needs to split on whitespace not just spaces. This is the default if you do not give an argument to the split() method.

Whitespace includes tabs.