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# Cannot get passed try:

I have tested this in the terminal with success, but for whatever reason it won't accept the answer here. Please see code.

trial.py
```def add(one, two):
try:
three = one + two
test = int(three)
except ValueError:
return(None)
fone = float(one)
ftwo = float(two)
fthree = fone + ftwo
return(fthree)
``` I arranged your code, I don't know why you have repeated code from the previous task, and there were some identation errors, also there was no else: statement (not neccessary in try-except, but the challenge mentioned it).

```def add(one, two):
try:
fone = float(one)
ftwo = float(two)
except ValueError:
return(None)
else:
fthree = fone + ftwo
return(fthree)
``` MOD

The last four lines of your code has an indentation issue. What are the last 4 lines intended to do? Did you mean to put and `else:` statement above them?

Your current code would fail because the conversion to floats add('4.5', '5.5')`since the`try`would concatenate them to '4.55.5' and fail to convert to int, then return`None` instead of converting to float.

Starting with Task 2, the challenge wants you to assume all addition be of floats. This means converting to float in the `try` section.

```def add(one, two):
try:
three = float(one) + float(two)
# test = int(three)
except ValueError:
return None  # <-- return does not need parens
# fone = float(one)
# ftwo = float(two)
# fthree = fone + ftwo
# return fthree   # <-- return does not need parens
return three
```

Additionally, the `return three` can be moved into the `try` block and eliminate the `else`:

```def add(one, two):
try:
# three = float(one) + float(two)
# return three
return = float(one) + float(two)
except ValueError:
return None
```

Many thanks!