Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

11,877 Points

Cant figure this out

Could any one offer a helping hand I am stuck in this challenge, thanks

$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  function showWeather(weatherReport) {

$.getJSON(weatherAPI, data, showWeather(jqXHR));

<!DOCTYPE html>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>

2 Answers

Steven Parker
Steven Parker
220,416 Points

You're really close!

You want to pass the callback function itself (by name) as the third argument, not invoke it and pass the result.

The difference between naming and invocation is the presence of the parentheses (optionally filled with one or more arguments).

11,877 Points

You sir are the real MVP, thanks a lot. It is crazy how when one gets frustrated we blind ourselves.