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JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

Javier MARQUEZ
Javier MARQUEZ
11,877 Points

Cant figure this out

Could any one offer a helping hand I am stuck in this challenge, thanks

weather.js
$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  }

$.getJSON(weatherAPI, data, showWeather(jqXHR));



});
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
</head>
<body>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>
  </div>
</body>
</html>

2 Answers

Steven Parker
Steven Parker
229,005 Points

You're really close!

You want to pass the callback function itself (by name) as the third argument, not invoke it and pass the result.

The difference between naming and invocation is the presence of the parentheses (optionally filled with one or more arguments).

Javier MARQUEZ
Javier MARQUEZ
11,877 Points

You sir are the real MVP, thanks a lot. It is crazy how when one gets frustrated we blind ourselves.

Thanks