Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Basics (2015) Number Game App Squared

Can't find the error in the challenge. Can anyone help me, please? Thank you

Can't find the error. I have revised the code a lot of times. Please, a little help?

squared.py
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimti

def squared(arg):
    try:
        entrada = int(input("Introduce un número: "))
    except ValueError:
        longitud = len(arg)
        return arg * longitud
    else:
        return entrada * entrada

2 Answers

Stuart Wright
Stuart Wright
41,102 Points

There's no need to ask the user for input, because an argument is already being passed to the function.

def squared(arg):
    try:
        entrada = int(arg)
    except ValueError:
        longitud = len(arg)
        return arg * longitud
    else:
        return entrada * entrada
Scott Jones
Scott Jones
5,397 Points

You can simplify this by doing

Def squared(arg)
Try:
    Return(int(arg)*int(arg))
Except ValueError:
    Return(arg*len(arg))