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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Can't get passed this

<?php

$flavor = vanilla;

echo "<p>Your favorite flavor of ice cream is "; <br /> echo $flavor; echo ".</p>"; echo "<p>Randy's favorite flavor is cookie dough, also!</p>";

?>

Hey this question has been asked quite a bit these past couple of days, search the forum with the PHP filter and you will find two or three threads about this.

8 Answers

Brian Molkovich
Brian Molkovich
11,333 Points

<?php $flavor = Rose; echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; if ($flavor == "cookie dough") echo "<p>Randy's favorite flavor is cookie dough, also!</p>";

?> This is a right answer? don't forget rate my help)

I tried all of them. None work.

Brian Molkovich
Brian Molkovich
11,333 Points

<?php

$flavor = vanilla;

echo "Your favorite flavor of ice cream is ".$flavor."."." Randy's favorite flavor is cookie dough, also!";

?>

Now I am more confused.

I have wasted 3 hours on this one and am about to quit this website. I NEED AN ANSWER for this.

Bummer! Be sure to update the output to include your flavor, without changing any of the other code.

Still doesn't work.

Not working for me.