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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Posted by Randy Crowson
Randy Crowson
2,531 Points

Can't get passed this

<?php

$flavor = vanilla;

echo "<p>Your favorite flavor of ice cream is "; <br /> echo $flavor; echo ".</p>"; echo "<p>Randy's favorite flavor is cookie dough, also!</p>";

?>

Leonardo Hernandez
Leonardo Hernandez
13,798 Points

Hey this question has been asked quite a bit these past couple of days, search the forum with the PHP filter and you will find two or three threads about this.

8 Answers

Brian Molkovich
Brian Molkovich
11,333 Points
Brian Molkovich
Brian Molkovich
11,333 Points

<?php $flavor = Rose; echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; if ($flavor == "cookie dough") echo "<p>Randy's favorite flavor is cookie dough, also!</p>";

?> This is a right answer? don't forget rate my help)

Randy Crowson
Randy Crowson
2,531 Points
Randy Crowson
Randy Crowson
2,531 Points

I tried all of them. None work.

Brian Molkovich
Brian Molkovich
11,333 Points
Brian Molkovich
Brian Molkovich
11,333 Points

<?php

$flavor = vanilla;

echo "Your favorite flavor of ice cream is ".$flavor."."." Randy's favorite flavor is cookie dough, also!";

?>

Randy Crowson
Randy Crowson
2,531 Points
Randy Crowson
Randy Crowson
2,531 Points

Now I am more confused.

Randy Crowson
Randy Crowson
2,531 Points
Randy Crowson
Randy Crowson
2,531 Points

I have wasted 3 hours on this one and am about to quit this website. I NEED AN ANSWER for this.

Randy Crowson
Randy Crowson
2,531 Points
Randy Crowson
Randy Crowson
2,531 Points

Bummer! Be sure to update the output to include your flavor, without changing any of the other code.

Still doesn't work.

Randy Crowson
Randy Crowson
2,531 Points
Randy Crowson
Randy Crowson
2,531 Points

Not working for me.