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Randy Crowson
2,531 PointsCan't get passed this
<?php
$flavor = vanilla;
echo "<p>Your favorite flavor of ice cream is "; <br /> echo $flavor; echo ".</p>"; echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
?>
8 Answers
Brian Molkovich
11,333 Points<?php $flavor = Rose; echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; if ($flavor == "cookie dough") echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
?> This is a right answer? don't forget rate my help)
Randy Crowson
2,531 PointsI tried all of them. None work.
Brian Molkovich
11,333 Points<?php
$flavor = vanilla;
echo "Your favorite flavor of ice cream is ".$flavor."."." Randy's favorite flavor is cookie dough, also!";
?>
Randy Crowson
2,531 PointsNow I am more confused.
Randy Crowson
2,531 PointsI have wasted 3 hours on this one and am about to quit this website. I NEED AN ANSWER for this.
Randy Crowson
2,531 PointsBummer! Be sure to update the output to include your flavor, without changing any of the other code.
Still doesn't work.
Brian Molkovich
11,333 Pointsi pass with this my challenge
Randy Crowson
2,531 PointsNot working for me.
Leonardo Hernandez
13,798 PointsLeonardo Hernandez
13,798 PointsHey this question has been asked quite a bit these past couple of days, search the forum with the PHP filter and you will find two or three threads about this.