Can't get Promise.all() to properly work

//more code above this
.then(function(urlArray){

  const v = urlArray.map(fn)

  Promise.all(v).then(console.log('FINISHED!'));
});

const fn = function scrapeShirtInformation(url){
  let finish = false;
  return new Promise((resolve, reject) => {
      request(url, function (error, response, body) {
        if (!error) {

          const $ = cheerio.load(body);

          let price = $('.price').text();
          let title = $(".shirt-details h1").text().substr(price.length + 1);
          let relativeImageUrl = $(".shirt-picture img").attr("src");
          let imageUrl = rootURL + relativeImageUrl;
          console.log('Writing data for: ' + url);

          let shirtInfo = {};
          shirtInfo.price = price;
          shirtInfo.title = title;
          shirtInfo.relativeImageUrl = relativeImageUrl;
          shirtInfo.imageUrl = imageUrl;

          //push shirt info into infoToWrite array
          infoToWrite.push(shirtInfo);

          console.log(infoToWrite);

          resolve(shirtInfo);
        } else {
            reject(console.log('FAIL!'));
            console.log(`An error was encountered: ${error.message}`);
        }
      });
    })
  }