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PHP Enhancing a Simple PHP Application Integrating Validation Errors Reviewing PHP Basics

Jason Slabbers
Jason Slabbers
4,447 Points
Posted by Jason Slabbers
Jason Slabbers
4,447 Points

Can't get return value of get_flavor.

I need some help with this code challenge.

i've tried many approaches to get the return value of get_flavor, but it will not work (step 3 in the challenge).

Can you help me with some tips where to look to get the right return value?

Many thanks in advance!

Jeff Busch
Jeff Busch
19,287 Points

Hi Jason, can we see your code?

4 Answers

Cherie Burgett
Cherie Burgett
8,711 Points
Cherie Burgett
Cherie Burgett
8,711 Points

get_flavor is already a predefined function so no need to rename it as a function again. You included it in step 1.

$flavor = get_flavor(); echo "Randy's favorite flavor of ice cream is " . $flavor . ".";

Jeff Busch
Jeff Busch
19,287 Points
Jeff Busch
Jeff Busch
19,287 Points

Jason,

You are adding a return statement to a function that already returns a value. We assigned the return value to $flavor aleady: $flavor = get_flavor();. Now we just use $flavor to use that value. Check it out below. Also:

If you look to the bottom right of the text box you will see something that says Markdown Cheetsheet. If you don't understand that maybe this will make sense: How to display code at Treehouse

Jeff

echo "Randy's favorite flavor of ice cream is " . $flavor . ".";
Jason Slabbers
Jason Slabbers
4,447 Points
Jason Slabbers
Jason Slabbers
4,447 Points 
<?php include("flavor.php"); ?>

<?php
function get_flavor() {
  $flavor = "";

  return $flavor;
}
?>
<?php

echo "Randy's favorite flavor of ice cream is " . $flavor . ".";

?>
Jason Slabbers
Jason Slabbers
4,447 Points
Jason Slabbers
Jason Slabbers
4,447 Points

Thanks Cherie! I was thinking 1 step to far I think.