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Rob Roberts
2,081 PointsCan't get this to work.
I thought I defined the Int return correctly, but keep getting "Int -> Int" is not convertible to Int.
func mathOperation(differenceBetweenNumbers: (Int, Int) -> Int, a: Int, b: Int -> Int) { return differenceBetweenNumbers(a,b) }
/**
For this code challenge, let’s define a math operation as a function that
carries out some work on two integers and returns an integer as well. An
example is the function below, `differenceBetweenNumbers`, which takes two
integers and calculates the difference between the numbers. After calculating,
it returns the difference.
*/
func differenceBetweenNumbers(a: Int, b:Int) -> (Int) {
return a - b
}
// Enter your code below
func mathOperation(differenceBetweenNumbers: (Int, Int) -> Int, a: Int, b: Int -> Int) {
return differenceBetweenNumbers(a,b)
}
1 Answer
Chris Adamson
132,143 PointsFor this exercise, you give the function parameter a different name than differenceBetweenNumbers, and move your return type outside of the parameter list. The return type is the same as the differenceBetweenNumbers method.
func mathOperation(mathFunc: (Int, Int) -> Int, a: Int, b: Int) -> Int {
return mathFunc(a,b)
}