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Python Python Collections (2016, retired 2019) Dictionaries Teacher Stats

Ashikur Rahman
Ashikur Rahman
129 Points
Posted by Ashikur Rahman
Ashikur Rahman
129 Points

Can't pass this step.

Can't build up logic for this step. Code attached. Anything helpful from you will be appreciate

teachers.py 
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.

def num_teachers(arg):

    return(len(arg))


def num_courses(arg):
    total = 0
    list = []
    for course in arg:
        list.append(len(arg[course]))
    total = sum(list)
    return(total)

def courses(c):
    teachcourse=[]
    for teach in c.values():
        teachcourse.extend(teach)
    return teachcourse

def most_courses():

def most_courses(arg):
    max_count = 0
    name = ""
    for value in arg.items():
        teacher = arg.keys() 
        courses = arg.values()
        max_count = max(courses)


        if len(courses) > len(max_count):
            name = teacher
    return name

1 Answer

Øyvind Andreassen
Øyvind Andreassen
16,839 Points
Øyvind Andreassen
Øyvind Andreassen
16,839 Points

Hi,

When I get stuck, I print out variables and check if they contain what I think they are suppose to contain.

for value in arg.items():
        teacher = arg.keys()
        courses = arg.values()
        max_count = max(courses)

These three variables don't hold the values that you want, rather returning

teacher returns: dict_keys(['Andrew Chalkley', 'Kenneth Love'])
courses returns: dict_values([['jQuery Basics', 'Node.js Basics'], ['Python Basics', 'Python Collections']])
max_count returns: ['jQuery Basics', 'Node.js Basics']

I would suggest that you change the loop to the following, and consider where your placing the assignment of max_count in the loop.

for key, value in arg.items():
      teacher = key
      courses = value

There are plenty of threads that will give you the answer, but I hope this helps you to figure out the solution. Just a heads up, consider the wording of the challenge. It asks you to return the name, not the names.