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Laknath Gunathilake1,860 Points
can't seem to pass the challenge
when I run the code it says TypeError: even_odd() takes 0 positional arguments but 1 was given
def even_odd(): number=int(input("enter number:")) if number%2==0: return True else: return False
Grigorij Schleifer10,364 Points
you can use this code:
you don´t need to ask the user for the number . Give the number as a method argument for the even_odd method.
def even_odd(number): # number is the methods argument
The rest ist fine :)