Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Michael Konstantinovsky
Michael Konstantinovsky
991 Points

Can't understand what is wrong?

It's works perfect in anaconda! Why I'm getting errors? Thanks!!!

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    freq = []
    string_1 = string.lower().split()
    for i in string:
    diction = dict(zip(string_1,freq))
    return diction

2 Answers

Maybe you meant:

for i in string_1:

in line:

for i in string:

Hope this helps!

Michael Konstantinovsky
Michael Konstantinovsky
991 Points

You are awesome!!!!! Thanks a lot, such a stupid mistake!!!