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Start your free trialChristopher Harrison
4,964 PointsCan't use a for loop to generate random num between 0 and 9 until getting 8?
In these practice problems, the doWhileLoops, whileLoops, and forLoops follow the basic pattern of exercises (same problems to solve). EXCEPT the forLoop doesn't involve the same 5th loop exercise of generating random numbers between 0 and 9 until you inevitably end in 8 (this exercise is in both of the other loop practice problems). So i'm wondering if it is even possible to create a forLoop to solve this problem. I tried, but couldn't get mine to work and am curious if it's possible. I'm new, so it very well could be simple and I'm just missing it :P Thanks guys! Here's the code I tried but didn't work for the solution in the console: for (let i = Math.floor(Math.random() * 10); i !== 8; i = Math.floor(Math.random() * 10)) { text += i + ' '; }
3 Answers
KRIS NIKOLAISEN
54,971 PointsI'm not sure if this is what you are after but I used an infinite loop and break statement as follows:
for (i = 0; i >= 0; i++){
j = Math.floor(Math.random() * 10);
console.log(j);
if (j === 8){ break;}
}
Ali Abbas
2,097 PointsHey Christopher,
This is just a great example of how each loop is suitable for particular tasks. When it comes to the for loops, there's no way of performing this task because it requires 3 arguments to work.
for (i = variable; i = condition; i = i + increments)
main problem here is that while using the for loop, you don't want to increment the random number. So, for this reason the for loop wouldn't be suitable for this task. I hope this helps, take care.
Peter Hope
Courses Plus Student 5,849 PointsI have written the code exactly as Joel has done (whileLoops Question 5 - Yes, I watched the solution) but, my number 8 is never printed, but Joels number 8 prints, then terminates. I wonder why?
Emilia Jacaszek
3,003 PointsI have the same problem :(
Firas Al-Mahrouqi
2,750 Pointsi = Math.floor(Math.random() * 10);
while ( i !== 8 ) {
text += i + ' ';
i = Math.floor(Math.random() * 10);
}
text += i;
You might be missing that very last line.
If the loop condition (i.e. i !==8) is met it will terminate, so you need that line outside of the loop body to concatenate the value of i to the text string.
Christopher Harrison
4,964 PointsChristopher Harrison
4,964 PointsI don't think I'm sure what the point of the i variable here is. If you loop runs based only on J.