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JavaScript

Car Prototytpe

I don't understand this question:

After the 'Car' constructor function, modify the Car's prototype to be the 'carPrototype':

var carPrototype = {
        model: "generic",
        currentGear: 0,
        increaseGear: function() {
          this.currentGear ++;
        },
        decreaseGear: function() {
          this.currentGear--;
        } 
      }

      function Car(model) {
    this.prototype. = carPrototype;
    this.model = model || carPrototype.model;
  }

//tests
console.log((new Car("Mazda")).model);
console.log((new Car("Sedan")).model);
console.log((new Car()).model);

any help?

3 Answers

Hey Douglas,

I just went through this course recently. I think it's a bit easier than you might realize, and the code that it is looking for is just like what was shown in the video. You want to set the prototype property of the Car constructor function. To do this you set Car.prototype equal to the the carPrototype.

      Car.prototype = carPrototype;

Hhmmmm...i added the code between the constructor function and the console.logs, like this:

var carPrototype = {
        model: "generic",
        currentGear: 0,
        increaseGear: function() {
          this.currentGear ++;
        },
        decreaseGear: function() {
          this.currentGear--;
        } 
      }

      function Car(model) {
    this.prototype. = carPrototype;
    this.model = model || carPrototype.model;
  }

      Car.prototype = carPrototype;

//tests
console.log((new Car("Mazda")).model);
console.log((new Car("Sedan")).model);
console.log((new Car()).model);

like in the video but it still says that it is wrong.

Chris, update on this thread....you solution to this part of the challenge did work - i had an extra decimal in the code, sorry. now if i can just get the third part.