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Simon Perez
Courses Plus Student 915 Pointschallenge 3, random.randint(1, 99).... I cannot see where is my mistake.
Take a look at my code, I cannot see the mistake, thanks in advance!
import random
start = 5
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
while start:
number = random.randit(1, 99)
if even_odd(number):
print("{} is even".format(number))
else:
print("{} is odd".format(number))
start -=1
3 Answers
Igor Ević
5,827 PointsYou have a syntax error: randit
Marcin Lubke
13,253 PointsIt's just a simple typo, here:
number = random.randit(1, 99)
should be:
number = random.randint(1, 99)
Agustin Fitipaldi
1,644 Pointsayyyy, almost! you forgot to use use 'num' instead of 'number' as the variable. the function even_odd takes the argument (num), so when you plug in 'number' it doesnt pass
Agustin Fitipaldi
1,644 Pointswoops, realized MY mistake, lol sorry 'bout that