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Python Python Basics (2015) Letter Game App Even or Odd Loop

Simon Perez
PLUS
Simon Perez
Courses Plus Student 915 Points

challenge 3, random.randint(1, 99).... I cannot see where is my mistake.

Take a look at my code, I cannot see the mistake, thanks in advance!

even.py
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    number = random.randit(1, 99)
    if even_odd(number):
        print("{} is even".format(number))
    else:
        print("{} is odd".format(number))
    start -=1

3 Answers

You have a syntax error: randit

Marcin Lubke
Marcin Lubke
13,253 Points

It's just a simple typo, here:

number = random.randit(1, 99)

should be:

number = random.randint(1, 99)
Agustin Fitipaldi
Agustin Fitipaldi
1,644 Points

ayyyy, almost! you forgot to use use 'num' instead of 'number' as the variable. the function even_odd takes the argument (num), so when you plug in 'number' it doesnt pass

Agustin Fitipaldi
Agustin Fitipaldi
1,644 Points

woops, realized MY mistake, lol sorry 'bout that