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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. # Challenge 5 not working

def stats(dict1): list1=[] count=0 for i in dict1: list2=dict1[i] for j in list2: count+=1 list1.append([i,count]) return list1

Can anyone please tell me whats wrong with this logic. This code is not working

teachers.py
```# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict1):
count=0
for i in dict1:
count+=1
return count

def num_courses(dict1):
count=0
for i in dict1:
list1=dict1[i]
for i in list1:
count+=1
return count

def courses(dict1):
list1=[]
for i in dict1:
list2=dict1[i]
for j in list2:
list1.append(j)
return list1

def most_courses(dict1):
d={}

for i in dict1:
list1=dict1[i]
count=0
for j in list1:
count+=1
d[i]=count
max1=0
for k in d:
if d[k]>max1:
max1=d[k]
ele=k
return ele

def stats(dict1):
list1=[]
count=0
for i in dict1:
list2=dict1[i]
for j in list2:
count+=1
list1.append([i,count])
return list1
``` Hi there, if you haven't seen my post in your other thread, naming variables more appropriately can't hurt when coding. The problem is that count has been declared outside of the loop so it never starts at zero to count all the items inside the list, so you have to move it inside the loop.

Rather than loop over a list to count all the items, it's much easier to use the len() function.

```def stats(dict1):
list1=[]
for i in dict1:
count=0  # you want count in here
list2=dict1[i]
for j in list2:
count+=1
list1.append([i,count])
return list1
```