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Rakshit H Ravishankar
1,309 PointsChallenge 5 not working
def stats(dict1): list1=[] count=0 for i in dict1: list2=dict1[i] for j in list2: count+=1 list1.append([i,count]) return list1
Can anyone please tell me whats wrong with this logic. This code is not working
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict1):
count=0
for i in dict1:
count+=1
return count
def num_courses(dict1):
count=0
for i in dict1:
list1=dict1[i]
for i in list1:
count+=1
return count
def courses(dict1):
list1=[]
for i in dict1:
list2=dict1[i]
for j in list2:
list1.append(j)
return list1
def most_courses(dict1):
d={}
for i in dict1:
list1=dict1[i]
count=0
for j in list1:
count+=1
d[i]=count
max1=0
for k in d:
if d[k]>max1:
max1=d[k]
ele=k
return ele
def stats(dict1):
list1=[]
count=0
for i in dict1:
list2=dict1[i]
for j in list2:
count+=1
list1.append([i,count])
return list1
1 Answer

Umesh Ravji
42,362 PointsHi there, if you haven't seen my post in your other thread, naming variables more appropriately can't hurt when coding. The problem is that count has been declared outside of the loop so it never starts at zero to count all the items inside the list, so you have to move it inside the loop.
Rather than loop over a list to count all the items, it's much easier to use the len() function.
def stats(dict1):
list1=[]
for i in dict1:
count=0 # you want count in here
list2=dict1[i]
for j in list2:
count+=1
list1.append([i,count])
return list1