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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Uday Girajavagol
Uday Girajavagol
1,127 Points

Challenge error

My code works very well in python work space and gives results as accepted. But I am getting error in Challenge. Is there any issue with my code ?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(sentence):
    dic={}
    lis = sentence.split(' ')
    for word in lis:
        num = lis.count(word)
        dic.update({word.lower():num})
    return dic

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Your external testing is likely not as rigorous as what the challenge does. But the "Bummer" message gave you a useful hint when it said "Be sure you're lowercasing the string and splitting on all whitespace!"

To split on "all whitespace" the argument to "split" should be left empty. Supplying a string literal argument with a space in it changes the behavior to split only on individual spaces.