Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Uday Girajavagol
Uday Girajavagol
1,127 Points

Challenge error

My code works very well in python work space and gives results as accepted. But I am getting error in Challenge. Is there any issue with my code ?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(sentence):
    dic={}
    lis = sentence.split(' ')
    for word in lis:
        num = lis.count(word)
        dic.update({word.lower():num})
    return dic

1 Answer

Steven Parker
Steven Parker
229,608 Points
Steven Parker
Steven Parker
229,608 Points

Your external testing is likely not as rigorous as what the challenge does. But the "Bummer" message gave you a useful hint when it said "Be sure you're lowercasing the string and splitting on all whitespace!"

To split on "all whitespace" the argument to "split" should be left empty. Supplying a string literal argument with a space in it changes the behavior to split only on individual spaces.