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# Challenge score_yatzy

if there is a yatzy (5 dices with the same number), then length of one of these lists would be 5. What am I missing here?

```def score_yatzy(self, hand):
if 5 in {len(hand.ones), len(hand.twos), len(hand.threes), len(hand.fours), len(hand.fives), len(hand.sixes)}
return 50
else:
return 0
```
scoresheets.py
```class YatzyScoresheet:
def score_ones(self, hand):
return sum(hand.ones)

def score_ones(self, hand):
return sum(hand.ones)

def score_ones(self, hand):
return sum(hand.ones)

def score_ones(self, hand):
return sum(hand.ones)

def score_ones(self, hand):
return sum(hand.ones)

def score_sixes(self, hand):
return sum(hand.sixes)

def _score_set(self, hand, set_size):
scores = 
for worth, count in hand._sets.items():
if count == set_size:
scores.append(worth*set_size)
return max(scores)

def score_one_pair(self, hand):
return self._score_set(hand, 2)

def score_chance(self, hand):
return sum(hand.ones) + sum(hand.twos) + sum(hand.threes) + sum(hand.fours) + sum(hand.fives) + sum(hand.sixes)

def score_yatzy(self, hand):
if 5 in {len(hand.ones), len(hand.twos), len(hand.threes), len(hand.fours), len(hand.fives), len(hand.sixes)}
return 50
else:
return 0
``` Hope this helps, make sure you understand!

```def score_yatzy(self, hand):
dicelist = []                             #a list to append same value dice
for dice in hand:                     #looping through to check all dice
dicelist.append(dice)
if dices == hand:           #you need to compare all dice
dicelist.append(dice)    #only append in list if they are the same
if len(dicelist) == 5:               #if that list gets 5 dice of same value = yatzy
return 50
else:                                       #if any of those dice didn't have the same value as hand != yatzy
return 0
```

Why are you appending twice? dicelist.append(dice)

Is that a typo?

Another option is to review what the _score_set method was doing and borrow that approach. Within that function there is hand._sets.items() which has captured a dictionary of the dice rolls and their associated counts and which we can loop through to find a count of 5.

```    def score_yatzy(self, hand):
for worth, count in hand._sets.items():
if count == 5:
return 50
return 0
```

Hopefully this helps in seeing the solution in a different way.

Another solution

```    def score_yatzy(self, hand):
for die in hand:
if hand.count(die) >= 5:
return 50
return 0
```

Here is my solution: ''' def score_yatzy(self, hand): if hand[1:] == hand[:-1]: return 50 else: return 0 '''