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JavaScript AJAX Basics (retiring) jQuery and AJAX Handle AJAX failures with jQuery

Posted by jyoti barman
jyoti barman
Courses Plus Student 1,280 Points

challenge task 2

challenge task 2

app.js 
$.get("missing.html", function(data) {
  $("#footer").html(data);
});
$.get("missing.html", function(data) { $("#footer").html(data); }).fail(function(jqXHR) {

alert(jqXHR.statusText);

});
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
</head>
<body>
  <div id="main">
    <h1>AJAX with jQuery</h1>
  </div>
  <div id="footer"></div>
  <script src="jquery.js"></script>
  <script src="app.js"></script>
</body>
</html>

1 Answer

Steven Parker
Steven Parker
231,268 Points
Steven Parker
Steven Parker
231,268 Points

All of your added code looks good. :+1:

But you replicated the originally provided code. Don't copy that code, just add the new parts to it.