Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Shopping List App Break

Emilio Andere
Emilio Andere
495 Points
Posted by Emilio Andere
Emilio Andere
495 Points

challenge task 2 of 2

Why is my answer wrong, intending?

breaks.py 
def loopy(items):
    for stuff in items:
        print(stuff)
    if stuff == "STOP"
        break

1 Answer

Henrik Christensen
seal-mask
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points
Henrik Christensen
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP".

You need to add the if statement inside the loop AND before the print() + you're missing a colon at the end of your if statement

Emilio Andere
Emilio Andere
495 Points
Emilio Andere
Emilio Andere
495 Points

def loopy(items): for stuff in items: if stuff == "STOP" print(stuff): break wrong now why?