Challenge Task 2 of 2 For this task, make WifiLamp adopt the ColorSwitchable protocol. In the implementation of the..

Question

No preview section to debug compiler error...

I'm having trouble making this work.

protocols.swift

// Declare protocol here
protocol ColorSwitchable{
func switchColor(color: Color)
}

enum LightState {
  case On, Off
}

enum Color {
  case RGB(Double, Double, Double, Double)
  case HSB(Double, Double, Double, Double)
}

class WifiLamp: ColorSwitchable {
  let state: LightState
  var color: Color



  init() {
    self.state = .On
    self.color = .RGB(0,0,0,0)
  }
    func switchColor(color: Color) -> Color{
    }
}

Answer 1 · 2016-03-12T21:38:05Z

March 12, 2016 9:38pm

Hey John!

The challenge does not state that there will be a return type in the func that was set as the stored property for the ColorSwitchable protocol. So the first thing to do would be to remove the return ( -> Color ) from your func.

Next, the func in your code doesn't set the color of the lamp to a new color. We are just creating the Class so there wont be a specific color here, that wont happen until an instance of this Class is created. So the body of the func would be self.color = color

Lastly, the func would go before init .

protocol ColorSwitchable {
    func switchColor(color: Color)
}

enum LightState {
    case On, Off
}

enum Color {
    case RGB(Double, Double, Double, Double)
    case HSB(Double, Double, Double, Double)
}

class WifiLamp: ColorSwitchable {
    let state: LightState
    var color: Color

    func switchColor(color: Color) {
        self.color = color
    }
    init() {
        self.state = .On
        self.color = .RGB(0,0,0,0)
    }
}

I know this answer is a bit delayed but I hope that others may find it helpful if they need some help on this challenge as well.

Answer 2 · 2016-02-16T22:08:50Z

February 16, 2016 10:08pm

Although you've defined a "switchColor" function in your class to conform to the ColorSwitchable protocol, you've defined it with a return type of "Color". Because of this, it isn't exactly the function listed in the protocol so your code still doesn't conform to the ColorSwitchable protocol.

To make it conform, you need to either get rid of the return type in the current "switchColor" function OR define another "switchColor" function without the return type (function names in Swift can be shared as long as the function signatures are different such as the parameters or return type).

(If you do decide to keep your current "switchColor" function as is, you'll need to return a type of "Color" or you'll get another error.)

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John Cotton

John Cotton

Challenge Task 2 of 2 For this task, make WifiLamp adopt the ColorSwitchable protocol. In the implementation of the..

2 Answers

Travis McCormick

Travis McCormick

Matthew Young

Matthew Young