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iOS Swift 2.0 Basics Swift Operators Working With Operators

Challenge Task 2 of 2 Great job with the first task! In this task, we have two math operations. Without computing

my code..

Let isGreater = "someOperation" >= "anotherOperation" Let isGreater = "someOperation" <= "anotherOperation"

operators.swift
// Enter your code below
let value = 200
let divisor = 5

let someOperation = 20 + 400 % 10 / 2 - 15
let anotherOperation = 52 * 27 % 200 / 2 + 5

// Task 1 - Enter your code below
let result = value % divisor
// Task 2 - Enter your code below
let isPerfectMultiple = (result == 0)
Let isGreater = "someOperation" >="anotherOperation"
Let isGreater = "someOperation" <="anotherOperation"

Great job with the first task! In this task, we have two math operations. Without computing the values of those operations, we'd like to know if the first operation, someOperation is greater than, equal to or less than anotherOperation. 
Use the greater than or equal to operator and assign the Boolean result of the comparison to a constant named isGreater.

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You did do a great job on the first step! I feel like you're overthinking the second step a bit. And there's at least one syntax error. You've typed Let isGreater instead of let isGreater. Remember, everything is case sensitive. The first example you wrote is almost there. Except that you're comparing strings instead of the value of those variables. Take a look:

let isGreater = someOperation >= anotherOperation

See all that math in the someOperation and the anotherOperation that's set up in the beginning? We're going to make the computer do that for us and then tell us which had the bigger number. If someOperation resulted in a number bigger than or equal to the number generated by anotherOperation, the boolean value of true will be assigned to isGreater. Hope this helps! :sparkles:

edited for technical correctness

Hello, thanks for correcting my error