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PHP PHP Basics (Retired) PHP Data & Structure PHP Variables

Posted by Logan Mayer
Logan Mayer
9,937 Points

Challenge Task 2 of 2 in PHP Basics

I feel like I must be missing something obvious because for whatever reason, I can't get passed this simple challenge. Anybody see what I'm missing? Thanks in advance for any help.

Challenge: "Now echo Mike's Name To The Screen".

Here is my code, which almost exactly matches what was in the video itself. I've surrounded it with 'body' and 'h1' tags as well and still nothing.

<?php $name = "Mike"; ?>

<h1> <?php echo $name ?> </h1>

Each time, I get this as a response:

Bummer! I am not seeing the word "Mike" in the output. Did you echo something different?

23 Answers

Ryan Watson
Ryan Watson
5,471 Points
Ryan Watson
Ryan Watson
5,471 Points

You are missing a semi-colon after the name variable in the echo statement, and you only need one php block.

both your variable decleration and your echo statement should go inside of a single php block

<?php

variable decleration here

echo statement here

?>

Ali Amirazizi
Ali Amirazizi
16,087 Points
Ali Amirazizi
Ali Amirazizi
16,087 Points

I found a possible fix. Refresh your browser and paste in the code again. Should Work.

Herkko Hietanen
Herkko Hietanen
30,501 Points
Herkko Hietanen
Herkko Hietanen
30,501 Points

Dear Treehouse,

Fix this as there really should be several ways to write the code and none of them are worse really wrong if they meet the task goals.

Adam N
Adam N
70,280 Points
Adam N
Adam N
70,280 Points

You're missing a semi-colon after the name variable, but with that fixed it's still not passing for me.

So technically you're right, Treehouse just doesn't want to give you your 6 points.

Atanas Sqnkov
Atanas Sqnkov
14,981 Points
Atanas Sqnkov
Atanas Sqnkov
14,981 Points 
<?php

$name = "Mike";
echo $name;

?>

This is what I wrote, and I am still getting the Bummer...

Atanas Sqnkov
Atanas Sqnkov
14,981 Points
Atanas Sqnkov
Atanas Sqnkov
14,981 Points

I placed a space between the semi-colon and the declarations and it worked!

Is it supposed to be this way?

Spenser Hale
Spenser Hale
20,915 Points

This worked for me thank you

Elijah Collins
Elijah Collins
19,457 Points
Elijah Collins
Elijah Collins
19,457 Points

There is a small bug because I wrote the exact same as everyone else here but this line of code should work

<?php 

$name = "Mike";
echo $name ;

?>

And no you shouldn't have to put spaces in between decelerations

kkswecpsyl
kkswecpsyl
8,155 Points

I have written it exactly as you have and still get the error.. wtf..

Elijah Collins
Elijah Collins
19,457 Points

David Brenecki I'm not sure where you're getting the error but a step by step is this

Open your php tags, then make a variable named "name" give it a string called "Mike"

<?php
$name = 'Mike';
?>

Echo $name

<?php 
$name = 'Mike';
echo $name;
?>
Adam Holms
Adam Holms
2,208 Points
Adam Holms
Adam Holms
2,208 Points

This is a browser issue. I was using Google Chrome with no avail and then tried using Internet Explorer and it worked just fine.

MUZ140787 Ricardo Chitagu
MUZ140787 Ricardo Chitagu
5,364 Points
MUZ140787 Ricardo Chitagu
MUZ140787 Ricardo Chitagu
5,364 Points

Treehouse u need to fix this

DeAndre Filer
DeAndre Filer
1,967 Points
DeAndre Filer
DeAndre Filer
1,967 Points

The problem is still not fixed

MUZ140970 Shaune Muringani
MUZ140970 Shaune Muringani
11,962 Points
MUZ140970 Shaune Muringani
MUZ140970 Shaune Muringani
11,962 Points

<?php $name = "Mike"; echo $name; ?> this worked for me after a long frustrating trials....

jasonjones5
PLUS
jasonjones5
Courses Plus Student 5,571 Points
jasonjones5
jasonjones5
Courses Plus Student 5,571 Points

This still doesn't work. Tried all the above fixes plus my own experimentation and nothing. Pretty poor to be frank.

Logan Mayer
Logan Mayer
9,937 Points
Logan Mayer
Logan Mayer
9,937 Points

Adam, you're right on the missing semi-colon but since it's on it's own line, I didn't think it was necessary, and they didn't include a semi-colon in the video.

After using Ryan's technique and putting everything inside of the same PHP block, it finally worked. I had assumed it wanted something in a separate block outside of the initial PHP block.

Thanks to both of you for your help!

mark uttecht
PLUS
mark uttecht
Courses Plus Student 9,012 Points
mark uttecht
mark uttecht
Courses Plus Student 9,012 Points

I had an issue with this challenge also, turns out I had a <b>blank line 1 and started my code on line 2</b>... deleting the empty line 1 and starting the code on the first line fixed the issue.

Maria Stommes
Maria Stommes
17,140 Points
Maria Stommes
Maria Stommes
17,140 Points

Can someone confirm that this is correct? I"m just wondering, because I went back to the video and it pretty much matches verbatim with the exception of the semicolon. (I think that with one line of Php you don't need the semi-colon???)

<?php $name="Mike";?>

<?php echo $name; ?>

David Lockie
David Lockie
7,959 Points
David Lockie
David Lockie
7,959 Points

<?php $name = "Mike"; echo $name; ?>

I did this and it said "Bummer! I am not seeing the word "Mike" in the output. Did you echo something different?"

Any suggestions?

George Akinian
George Akinian
17,615 Points
George Akinian
George Akinian
17,615 Points 
<?php $name = "Mike"; echo $name; ?>

This code works.

Craig Vanwyk
Craig Vanwyk
1,063 Points

It worked for me

Chris Reynolds
Chris Reynolds
3,627 Points
Chris Reynolds
Chris Reynolds
3,627 Points

I had the same issue, until I backspaced the opening <?php so there was was no whitespace at the start, then bingo.

Wouldn't be an issue in reality, bug with the test.

Brendan Mahoney
Brendan Mahoney
10,163 Points
Brendan Mahoney
Brendan Mahoney
10,163 Points

Yeah, I would try a simple refresh to those of you still having issues. It's unlikely that it's an actual issue with your content. Luckily these steps are fairly painless so a refresh won't lose much progress.

Should work after.

DeAndre Filer
DeAndre Filer
1,967 Points
DeAndre Filer
DeAndre Filer
1,967 Points

<?php

$name = "Mike"; echo $name;

?>

I am trying the same code and not working.

Ryan Watson
Ryan Watson
5,471 Points
Ryan Watson
Ryan Watson
5,471 Points

I'm not sure what the issue is. Your code looks right other than it is not best practice to put two statements on one line, but when I run the code from your example, it works. The code provided below works for me in Chrome Version 43.0.2357.134 m, Firefox Version 39.0, IE Version 11.0.9600.17905, Safari Version 5.1.7 for windows. Hope this helps.

<?php

$name = "Mike";

echo $name;

?>
Mayker Reyes
Mayker Reyes
3,987 Points

Use IE and it will work.

<?php $name = "Mike" ; echo $name ;

?>

Felicia Mabuza
Felicia Mabuza
9,408 Points
Felicia Mabuza
Felicia Mabuza
9,408 Points

<?php $name = 'Mike';

echo $name;

?>

This is the same code that everyone has. If you are having the same issue with the error message even though your code matches, try refreshing the page and putting the code in again; that eventually worked for me after trying multiple solutions that were to no avail.

Ashenafi Ashebo
Ashenafi Ashebo
15,021 Points
Ashenafi Ashebo
Ashenafi Ashebo
15,021 Points

<?php

$name = "Mike";

?>

<!DOCTYPE html> <html> <?php echo "Mike"?> </html>

Ashenafi Ashebo
Ashenafi Ashebo
15,021 Points
Ashenafi Ashebo
Ashenafi Ashebo
15,021 Points

don't forget to include the the the doctype