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Python Python Basics (2015) Shopping List App Break

Posted by olusola ojo
olusola ojo
Courses Plus Student 498 Points

challenge task 2 of 2 - shopping list app

"Challenge Task 2 of 2

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!"

I just don't get what I am doing wrong, Pls help, here's my code below.

breaks.py 
def loopy(items):
    # Code goes here

    for thing in items:
        print (items)
        elif items == "STOP":
            break

3 Answers

Oszkár Fehér
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Oszkár Fehér
Treehouse Project Reviewer
Oszkár Fehér
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Oszkár Fehér
Treehouse Project Reviewer

Hi Ojo If we write the code for you, it will not be for your help. Your loop starts ok but before you print() out anything you should check if it contains "STOP"

if thing == "STOP"

if this condition is correct than break the loop. After this check you should print() the rest

print(thing)

elif statement can't start first an if statement, it's a short of else if statement, if there is no if it can't be an elif, I hope this helps you to understand a little bit better the if statement and I also hope it was for your help. Keep up the good coding.

nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points

Hi, it looks to me like you've almost got that bit of coding. But instead of an "elif" statement you need and "if" statement, and your "if" statement needs to go before your "print." Like this:

def loopy(items): for item in items: if item == 'STOP': break print (item) Hope it helps. : )

nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points

Opps! I didn't realize it would put that out of order.

nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points 
def loopy(items):
    for item in items:
        if item == 'STOP':
            break
        print (item)