Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.Start your free trial
Daniil Ponomarenko902 Points
Challenge Task 2of2
I dont understand how to solve this challenge. If I start that function like this: loopy(["item1", "item2", "item3", "STOP", "item4"]) then everything is fine but without making it as list i dont know. It wont let me go farther.
def loopy(items): for item in items: print (item) if item == "STOP": break
Kurt Maurer16,725 Points
Your code as it is written will print "STOP", then run the conditional to break out of the loop. You should check to see if the item is "STOP" and break out of the loop without printing it.
for item in items: if item == "STOP": break print(item) #Note: you don't need a space between the print and parentheses