Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Posted by Yele X.
Yele X.
5,537 Points

Change the value in the flavor variable to cookie dough. Preview the code and make sure the message appears.

The prompt suggests that all that is necessary is to change the variable value to "cookiedough". Once I change the value, however, the challenge still fails.

Is there something I am missing?

index.php 
<?php
$flavor = "cookiedough";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookiedough") {
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
} 

?>

3 Answers

Yele X.
Yele X.
5,537 Points
Yele X.
Yele X.
5,537 Points

Joe Mills James Best

Here is the screenshot from after I change that value. As I said before, this code fails.

Kris Phelps
Kris Phelps
7,609 Points
Kris Phelps
Kris Phelps
7,609 Points

I might be mistaken, but if I recall, the flavor should be "Cookie Dough"

Yele X.
Yele X.
5,537 Points
Yele X.
Yele X.
5,537 Points

Kris Phelps You were right. How silly. I just spelled it without the space because that's how it is in the pre-written code that is already provided.

omg.

Kris Phelps
Kris Phelps
7,609 Points
Kris Phelps
Kris Phelps
7,609 Points

It's all good. I'm glad I could help :-)