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PHP PHP Basics Unit Converter Manipulating Numbers

Jessica Murillo
Jessica Murillo
9,119 Points
Posted by Jessica Murillo
Jessica Murillo
9,119 Points

Changing Integer Value

It tells me to add 4 to $integerOne and subtract one from for $intergerTwo but when I add 5 to $integerOne like this $integerOne = 1+5; it tells me that $integerOne does not equal one. So I add 5 the way that I did at the bottom and when I echo out the the value it shows that it equals 6 but then I get the error saying that I haven't change the value of $intergerOne. I am not sure what I am doing wrong and I bet it is something that I am just over looking but I need help! I would really appreciate it!

index.php 
<?php

//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$floatOne = 1.5;

$integerOne + 5;
$integerTwo - 2;
?>

2 Answers

Baki Baklan
Baki Baklan
5,915 Points

Hello there, what you did is actually correct, except one thing. You did the calculations correctly but you didn't assign it to a variable so you need to fix it. With the following syntax, you can fix it =)

$integerOne = $integerOne + 5; // Or shortly: $integerOne += 5;

$integerTwo = $integerTwo - 1; // Or shortly: $integerTwo -= 1;

Since you assign the calculations you made, it needs to be fixed. Happy coding :)

Jessica Murillo
Jessica Murillo
9,119 Points
Jessica Murillo
Jessica Murillo
9,119 Points

OMG! Lol yes, I forgot to set the value of integerOne and integerTwo. Thank you!

Antonio De Rose
Antonio De Rose
20,884 Points
Antonio De Rose
Antonio De Rose
20,884 Points 
<?php
$integerOne = 1;
$integerTwo = 2;
$floatOne = 1.5;

//firstly, you've been asked to add 5, and subtract 1
//now, is this how you re-assign values, for variables, when you add or subtract
//shouldn't you be needing another operator, right in front of the plus and minus operator

$integerOne + 5;
$integerTwo - 2;