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iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

Michael Flowers
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Michael Flowers
iOS Development with Swift Techdegree Graduate 10,917 Points
Posted by Michael Flowers
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Michael Flowers
iOS Development with Swift Techdegree Graduate 10,917 Points

changing print to return makes the code not work.

func fizzBuzz(n: Int) -> String { // Enter your code between the two comment markers for n in 1...100 { if n % 5 == 0 && n % 3 == 0 { print("FizzBuzz") // return "FizzBuzz" } else if n % 3 == 0 { print("Fizz") // return "Fizz" } else if n % 5 == 0 { print("Buzz") // return "Buzz" } } // End code return "(n)" }

this code works without the return, but when the return replaces the print statement, it does not work. Any help on the solution would be greatly appreciated.

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
   for n in 1...100 {
        if n % 5 == 0 && n % 3 == 0 {
            //print("FizzBuzz")
            return "FizzBuzz"
        } else if n % 3 == 0 {
           // print("Fizz")
            return "Fizz"
        } else if n % 5 == 0 {
           // print("Buzz")
            return "Buzz"
        } 
    }
  // End code
  return "\(n)"
}

1 Answer

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,967 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,967 Points

The challenge states: The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that.

Remove the loop.