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akhter ali
15,778 Pointsclassmethod confusion
I've created my class method which returns a list of the converted "dash" or "dot". Judging by the question, this is what it is supposed to return, in the order it was input to the class. However it still reports it didn't get the "right" output. This is what I've returned locally.
>>> test = Letter.from_string("dot-dot")
>>> test.pattern
['.', '.']
>>> test = Letter.from_string("dot-dash")
>>> test.pattern
['.', '-']
>>> type(test.pattern)
<class 'list'>
>>>
I wonder if it's looking for a tuple with a list inside.
class Letter:
def __init__(self, pattern=None):
self.pattern = pattern
def __iter__(self):
yield from self.pattern
def __str__(self):
output = []
for blip in self:
if blip == '.':
output.append('dot')
else:
output.append('dash')
return '-'.join(output)
@classmethod
def from_string(cls, string):
patternList = []
stringList = string.split('-')
for item in stringList:
if item.lower() == 'dash':
patternList.append('-')
elif item.lower() == 'dot':
patternList.append('.')
return cls(patternList)
class S(Letter):
def __init__(self):
pattern = ['.', '.', '.']
super().__init__(pattern)
1 Answer

andren
28,538 PointsDespite the name the dash string is actually supposed to be translated to an _ , not a -.
If you fix that discrepancy like this:
class Letter:
def __init__(self, pattern=None):
self.pattern = pattern
def __iter__(self):
yield from self.pattern
def __str__(self):
output = []
for blip in self:
if blip == '.':
output.append('dot')
else:
output.append('dash')
return '-'.join(output)
@classmethod
def from_string(cls, string):
patternList = []
stringList = string.split('-')
for item in stringList:
if item.lower() == 'dash':
patternList.append('_')
elif item.lower() == 'dot':
patternList.append('.')
return cls(patternList)
class S(Letter):
def __init__(self):
pattern = ['.', '.', '.']
super().__init__(pattern)
Then your code will be accepted.
akhter ali
15,778 Pointsakhter ali
15,778 PointsThanks, this should really be renamed to "Underscore-dot" to avoid confusion perhaps.