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iOS Closures in Swift 2 First Class Functions Extending the Int Type

Posted by Aditya Ramabadran
Aditya Ramabadran
3,746 Points

"Closest multiple of six?"

Hi,

thanks for this video @pasan! I have a quick, slightly irrelevant question: is that the correct implementation of "closest multiple of six"?

I think your function finds the closest multiple of six to the 'value' greater than or equal to the value. For example, for 32 (your first example test), 30 is closer than 36 to it and is still a multiple of 6.

Thanks!

Ali Salama
Ali Salama
5,889 Points
Ali Salama
Ali Salama
5,889 Points

If anyone is interested, here's a function that does it properly.

func closestMultipleOfSix(value: Int)->Int{

    let sixMultiple = Double(value) / 6

    let answer = Int((value % 6 > 3) || value <= 3  ? ceil(sixMultiple) : floor(sixMultiple)) * 6

    return answer

}

2 Answers

Daniel Cohen
Daniel Cohen
5,785 Points
Daniel Cohen
Daniel Cohen
5,785 Points

I like Ali's method, though I would use an extra set of parentheses around the OR part of the logic to make it clearer.

I did my much less elegant function like this: 

func closestMultipleOfSix(value: Int) -> Int {
    for x in -2...3 {
        if (value + x) % 6 == 0 {
            return value + x
        }
    }
    return 0
}

Technically 0 is a multiple of all numbers so you don't need code against getting 0 as an answer.

Julian Regan
Julian Regan
3,430 Points
Julian Regan
Julian Regan
3,430 Points

Though my answer's a little longer, I think it's as simple and readable as possible:

func closestMultipleOfSix(value: Int) -> Int {
    let remainder = value % 6
    if remainder < 3 {
        return value - remainder
    } else {
        return value + (6 - remainder)
    }
}

Note that I'm rounding up for values that lie halfway between two multiples