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###### Rebecca Spiller

461 Points# Code Challenge 2 - While Loops

Okay, I don't know whether I've just crammed too much in too short a time or if I'm truly missing something obvious here. My first task was to create this while loop:

```
let numbers = [2,8,1,16,4,3,9]
var sum = 0
var counter = 0
while counter < numbers.count {
sum += numbers[counter]
counter += 1
}
```

The next part of the task is as follows: Now that we have the while loop set up, it's time to compute the sum! Using the value of counter as an index value, retrieve each value from the array and add it to the value of sum.

For example: sum = sum + newValue. Or you could use the compound addition operator sum += newValue where newValue is the value retrieved from the array.

I keep drawing a blank, no matter how many times I read the question. I know it's probably something very basic as well. Please can someone break it down for me?

Thank you!

###### Rebecca Spiller

461 PointsSorry Steve, it's the second part of the challenge which is where I'm getting stuck. Computing the sum itself.

## 3 Answers

###### Steve Hunter

57,696 PointsOK Rebecca,

That's fine. You clearly understand it as you've got the code correct!

So, we're iterating of an array of numbers. That's called `numbers`

. To make sure we're not stuck in a continuous loop, we're using a counter variable which increments at each iteration. The loop stops when `counter`

is no longer less than the length of the array.

*Inside* the loop, aside from the incrementation, we're adding up each of the elements within the array. We access arrays by using square brackets and an index number. So, let's take:

```
let numbers = [2,8,1,16,4,3,9]
```

... this array. You access the first element (we start counting at zero for this) by using `numbers[0]`

. That gives us access to the first element, the integer '2'. In this, we're wanting to access each element in turn. So we're utilising the `counter`

variable as the index to access the array with. So, we set `counter`

to zero at the outset, and in the first loop within the `while`

loop, we use `numbers[counter]`

to perform the same task as `numbers[0]`

. In each successive loop, the value held by `counter`

is increased by one, giving us access to `numbers[1]`

then `numbers[2]`

etc, until we run out of elements and the loop stops.

Now we've accessed each element in turn, we add up each one into the `sum`

variable. Again, this is set to zero at the outset. We then add into it `numbers[0]`

. You've used `+=`

which adds the value to the right into the existing value on the left of it. You could use the longhand version:

```
sum = sum + numbers[counter]
// same as
sum += numbers[counter]
```

By the time the loop has ended, you have added *every* element of the array into `sum`

.

Does that clear things up a bit?

Steve.

###### Steve Hunter

57,696 PointsHi Rebecca,

Your code passed the challenge here - I suggest copying it and refreshing the challenge, then pasting the code back in.

Steve.

###### Rebecca Spiller

461 PointsHi Steve,

It's the second task of that challenge - computing the sum. I've re-read the question several times and it's just not making sense. Thanks!

###### Rebecca Spiller

461 PointsThank you! Explaining like that clears up in my mind which part is the computing the sum. Sorry if I didn't make myself very clear, I think my brain is a little bit frazzled from cramming so much into it.

###### Steve Hunter

57,696 PointsNo problem! As long as it is clear now ...

## Steve Hunter

57,696 Points## Steve Hunter

57,696 PointsLooks fine - what error is it giving you? (I'm just finding the challenge now ... )