Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Ruby Ruby Loops Build a Simple Contact List Methods That Return a Value

Posted by Leonardo Escalante
Leonardo Escalante
3,190 Points

Code challenge

Hello! please help me with this code because I couldn't ran it:

def parse_answer(answer, kind="string") answer = gets.chomp answer = answer.to_i if kind == "number" return answer end

Thanks!

ask.rb 
def parse_answer(answer, kind="string")
  answer = gets.chomp
  answer = answer.to_i if kind == "number"
  return answer
end

1 Answer

Arturo Alviar
Arturo Alviar
15,739 Points
Arturo Alviar
Arturo Alviar
15,739 Points

Hi Leonardo,

You almost have the right answer. In this case, answer will be passed in as a parameter so there is no need for the gets.chomp method. If you remove the answer = gets.chomp line, you will get the correct solution.

Here is another way to do it in one line using the ternary operator.

def parse_answer(answer, kind="string")
  return kind === "number" ? answer.to_i : answer # if kind==="number" then return answer.to_i else return answer
end

Hope this helps!