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###### Nils Garland

18,416 Points# Code challenge does not make ANY sense

First of all does anybody know the solution to this and can explain what's wrong

```
var results: [Int] = []
var even = 0
var odd = 1
for n in 1...100 {
// Enter your code below
if n % 2 = 0 || n * 7 {
print("Even")
} else {
print("Odd")
// End code
}
```

Second of all why do they do this? Why do they confuse us with weird challenges that don't make any sense. Anyway it's not like they would change it. The videos are super outdated yet they stick with them. We pay a stupid amount for this stuff and we can't get an updated version of the courses. Ridiculous.

## 1 Answer

###### Jennifer Nordell

Treehouse TeacherHi there! I believe you're referring to this challenge but please correct me if I'm wrong.

Let's take another look at the instructions:

For this challenge, we'd like to know in a range of values from 1 to 100, how many numbers are both odd, and a multiple of 7. To start us off, I've written a for loop to iterate over the desired range of values and named the local constant n. Your job is to write an if statement inside the for loop to carry out the desired checks. If the number is indeed both an odd number and a multiple of 7, append the value to the results array provided. Hint: To check for an odd number use the not operator to check for "not even"

What it's asking us to do is go through the list of numbers from 1 to 100. Every time we hit a number that's both odd (not evenly divisible by 2) and evenly divisible by 7 we'll put it in our results array. So 7 will go in our array and 21, but 14 will not as it is even.

A number is even if it is evenly divisible by 2. We check for this with the modulus operator `%`

. Which you've done in your code above. But we need it to be odd, not even. We can do the same thing to find if a number is evenly divisible by 7. A number is evenly divisible by 7 if the number modulus 7 is equal to 0.

There is no mention anywhere in the instructions of printing anything. We also do not need variables `even`

and `odd`

. A number is even if it is evenly divisible by 2.

Take a look at my solution:

```
var results: [Int] = []
for n in 1...100 {
// Enter your code below
if(n % 2 != 0 && n % 7 == 0){
results.append(n);
}
// End code
}
```

For further reference the modulus operator was covered in this video at around 2:27.

And the append() method was covered in this video at around 0:39.

Hope this helps!

## Nils Garland

18,416 Points## Nils Garland

18,416 PointsThank you once again :)