Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Code Challenge for iterating through dictionary

I can't figure out what I'm doing wrong.

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(my_string):
    my_string = my_string.lower()
    my_list = my_string.split()
    my_dict = {}
    for word in my_list
        count = 0
        for word2 in my_list
            if word == word2
        my_dict[word] = count
    return my_dict

The name of the error?

Unfortunately all I get is "Bummer, try again"

Actually, nevermind. I don't know why I didn't think to do it earlier, but I threw it into a file on my computer and ran it locally and the issue was syntax. Forgot the ":" in the "for" and "if" statements. Wish the error messages were better on the challenges. Thank you for replying though!

Anytime! Just keep mind that "bummer" mean a typo or something in your code not a run-time error