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PHP

Posted by Vince Brown
Vince Brown
16,249 Points

CODE CHALLENGE Grouping, Joining and Cleaning , Calculating AVG MYSQL

Like before, select the average "score" as "average", setting to 0 if null, by grouping the "movie_id" from the "reviews" table. Also, do an outer join on the "movies" table with its "id" column and display the movie "title" before the "average". Finally, filter out any "average" score over 2.

I have been stuck on this one for a while I cant seem to figure it out

I have tried

SELECT title,IFNULL(AVG(score),0 AS average)
FROM movies LEFT OUTER JOIN reviews
ON movies.id = reviews.movie_id
GROUP BY movie_id HAVING average < 2;


ALSO




SELECT title,IFNULL(AVG(score),0 AS average)
FROM reviews RIGHT OUTER JOIN movies
ON movies.id = reviews.movie_id
GROUP BY movie_id HAVING average < 2;

Also a lot of variations in between I have a feeling it might be something with the syntax? Any help would be great

1 Answer

JT Keller
JT Keller
12,731 Points

You've categorized this under PHP so I'm assuming that this is for the PHP/SQL unit (I haven't completed) and not just the SQL unit...anyway...running this in workbench gives a valid answer...not sure how your columns are setup.

SELECT title,IFNULL(AVG(score),0) AS Average
FROM movies LEFT OUTER JOIN reviews
ON movies.id = reviews.movie_id
GROUP BY movie_id HAVING average < 2;
Vince Brown
Vince Brown
16,249 Points

Thank you JT! It was a syntax error i was overlooking if you look at my code about I have the AS keyword creating the alias inside the IFNULL parameters.