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Start your free trialRicky Sparks
22,249 PointsCode Challenge Help??? What's wrong with my code?
We have a button in the ActionBar that will present a list of choices to the user. In the switch statement below, start by declaring an AlertDialog Builder and initializing it with the constructor. Use this for the context.
import android.app.Activity;
import android.app.AlertDialog;
import android.app.AlertDialog.Builder;
import android.content.DialogInterface;
import android.content.DialogInterface.OnClickListener;
import android.view.MenuItem;
public class MainActivity extends Activity {
protected DialogInterface.OnClickListener mDialogListener = new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
}
};
// Some code omitted!
@Override
public boolean onOptionsItemSelected(MenuItem item) {
int itemId = item.getItemId();
switch(itemId) {
case R.id.action_button:
break;
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setItems(R.array.list_choices, mDialogListener);
}
return super.onOptionsItemSelected(item);
}
}
1 Answer
james white
78,399 PointsSorry, Paolo,
but this may get Ricky further if he is dealing with the
"Presenting a List of Choices in Dialog Challenge": http://teamtreehouse.com/library/presenting-a-list-of-choices-in-a-dialog
switch(itemId) {
case R.id.action_button:
//for challenge 1 of 3
AlertDialog.Builder builder = new AlertDialog.Builder(this);
//for challenge 2 of 3
builder.setItems(R.array.genres, mDialogListener);
//for challenge 3 of 3
AlertDialog dialog = builder.create();
dialog.show();
break;
}
Ricky Sparks
22,249 PointsThanks :D
Paolo Scamardella
24,828 PointsPaolo Scamardella
24,828 PointsI'm not sure what you are trying to do, but after doing a quick view of your code, you switch statement is wrong. Your break statement is before your code, which means it will never get executed. Your code needs come first.