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PHP

Posted by Jeffrey Vierra
Jeffrey Vierra
25,404 Points

Code Challenge Variables and Conditions - Final Challenge

Hey Guys

I've been stuck on this challenge

"Change the value in the flavor variable to cookie dough. Preview the code and make sure the message appears."

My Code

<?php $flavor = "vanilla"; if ($flavor == "vanilla") echo "<p>Your favorite flavor of ice cream is "; echo "vanilla"; echo ".</p>"; $flavor = "cookie dough"; if ($flavor == "cookie dough") echo "<p>Randy's favorite flavor is cookie dough, also!</p>";

?>

I believe im doing what the challenge is asking. Yet im still getting a "Oops" error. I've tried this with several different options with the same result.

Please advise and thank you in advance.

Pavol Almasi
Pavol Almasi
Courses Plus Student 1,524 Points

hint 1: you declared the $flavor variable twice. Once with value of vanilla and second time (which overwrites the first value) you set it to cookiedough. Should be declared only once. If this is the step 4/4 then $flavor should have a value of "cookie dough. hint 2: your final output should read: your favorite flavor of ice cream is cookie dough. Randy's favorite ice cream is cookie dough also.

6 Answers

Kiya Appling
PLUS
Kiya Appling
Courses Plus Student 3,959 Points
Kiya Appling
Kiya Appling
Courses Plus Student 3,959 Points

Hello guys I too am having an issue with 4/4 my code:

<?php $flavor = "cookie dough"; echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; if ($flavor == "cookie dough") {echo "Randy's favorite flavor is cookie dough, also!";} ?>

When I preview it the code works as it should

However when I submit it this error is thrown back:

Oops! It looks like Task 3 is no longer passing.

Chase Lee
Chase Lee
29,275 Points
Chase Lee
Chase Lee
29,275 Points

Just make one $flavor variable and give it a value of "cookie dough" then make the second echo statement have a value of $flavor.

Next take the first conditional out and then put the last echo statement in curly braces.

Hope that makes sense and helps.

Jeffrey Vierra
Jeffrey Vierra
25,404 Points
Jeffrey Vierra
Jeffrey Vierra
25,404 Points

Thanks for the response Chase.

I keep getting a "Oops! It looks like Task 2 is no longer passing."

Am receiving the correct answer through.

(Randy's favorite flavor is cookie dough, also! )

<?php

$flavor = "cookie dough"; if ($flavor == "vanilla")

echo "Your favorite flavor of ice cream is ";

$flavor = "cookie dough";

if ($flavor == "cookie dough") {echo "Randy's favorite flavor is cookie dough, also!";} ?>

Chase Lee
Chase Lee
29,275 Points
Chase Lee
Chase Lee
29,275 Points

Take out:

if ($flavor == "vanilla")

And the second:

$flavor = "cookie dough";

Then echo $flavor after your first echo statement and the a period.

Jeffrey Vierra
Jeffrey Vierra
25,404 Points
Jeffrey Vierra
Jeffrey Vierra
25,404 Points

What an aha moment. My code finally worked.

Thanks guys for the quick responses.

Christian Torres
Christian Torres
3,795 Points
Christian Torres
Christian Torres
3,795 Points

i keep on getting this: Bummer! Be sure to add a conditional to hide the message.

here is my code-

<?php $flavor = "cookie dough"; $flavor = 'vanilla'; if ($flavor == vanilla) { echo "<p>Your favorite flavor of ice cream is "; } echo "vanilla"; echo ".</p>"; if ($flavor == "cookie dough") { echo "Randy's favorite flavor is cookie dough, also!"; } echo "."; ?>