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### Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. # Code Improvement - Stats Challenge

Looking to improve my code. It's definitely messy and this is the first problem that gave me a good challenge.

```    my_dict = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
'Kenneth Love': ['Python Basics', 'Python Collections', 'Python Stuff', 'Python other stuff']}

def most_classes(dicts):
max_count = 0
teacher_name = None
for key in dicts:
if len(dicts[key]) > max_count:
max_count = len(dicts[key])
teacher_name = key
return teacher_name

print(most_classes(my_dict))

def num_teachers(dicts):
teacher_number = len(dicts.keys())
return teacher_number

print(num_teachers(my_dict))

def stats(dicts):
the_list = []
for key in dicts:
teacher_name = key
num_classes = len(dicts[key])
new_list = [teacher_name, num_classes]
the_list.append(new_list)
return the_list

print(stats(my_dict))

def courses(dicts):
courses = []
for key in dicts:
courses += dicts[key]
return courses

print(courses(my_dict))
``` These functions can be compacted into one-liners, using list comprehension, lambda, and reduce (which are probably concepts that are introduced later or in more advanced courses):

```from functools import reduce

def stats(dicts):
return [ [key, len(dicts[key])] for key in dicts ]

def most_classes(dicts):
return reduce(lambda x,y: x if x > y else y, stats(dicts))

def num_teachers(dicts):
return len(dicts.keys())

def courses(dicts):
return [ dicts[key] for key in dicts ]
```