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Dorota Parzych
5,706 Pointscode problem-syntax error
num = input("Please enter number: ")
def how_big(number): if number <= 10 print("za malo") else number > 11 print("za dużo") elif number == 11 print("Idealnie")
how_big(num)
Inline 4 there is a syntax error - don't know how to fix it
2 Answers
KRIS NIKOLAISEN
54,967 PointsSee the first example here. It is close to what you are trying to do. Notice:
- if, elif, else statements end with a colon
- else comes last and has no condition. It is what runs when all other conditions are false
- the input is converted to an integer before being compared to other numbers
KRIS NIKOLAISEN
54,967 PointsConvert number to int before passing to the function. This can be done with the input:
num = int(input("Please enter number: "))
def how_big(number):
if number <= 10:
print("not enough")
elif number == 11:
print("perfect")
else :
print("too much")
how_big(num)
Dorota Parzych
5,706 PointsDorota Parzych
5,706 Pointsso now it looks like this... num = input("Please enter number: ")
def how_big(number): if int(number) <= 10: print("not enough") elif number == 11: print("perfect") else : print("too much")
how_big(num)
Generally, it works but when I type 11 it shows me that it is too much - why and how to fix that?