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# code problem-syntax error

num = input("Please enter number: ")

def how_big(number): if number <= 10 print("za malo") else number > 11 print("za duÅ¼o") elif number == 11 print("Idealnie")

how_big(num)

Inline 4 there is a syntax error - don't know how to fix it

See the first example here. It is close to what you are trying to do. Notice:

• if, elif, else statements end with a colon
• else comes last and has no condition. It is what runs when all other conditions are false
• the input is converted to an integer before being compared to other numbers

so now it looks like this... num = input("Please enter number: ")

def how_big(number): if int(number) <= 10: print("not enough") elif number == 11: print("perfect") else : print("too much")

how_big(num)

Generally, it works but when I type 11 it shows me that it is too much - why and how to fix that?

Convert number to int before passing to the function. This can be done with the input:

```num = int(input("Please enter number: "))

def how_big(number):
if number <= 10:
print("not enough")
elif number == 11:
print("perfect")
else :
print("too much")

how_big(num)
```