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pgmd
6,897 PointsCode question
function compare(a,b) { console.log(a+"<"+b, a<b); }
not sure what this does!
4 Answers
Tristan Gaebler
6,204 PointsIt takes two arguments (a and b), and compares them. When you call the function you input 2 numbers ( a and b), then the body of the function compares them. It logs to the console a then the character "<" then b. Then compares and b to see if it is true.
pgmd
6,897 PointsIn full example: function compare(j,c) { console.log(j+"<"+c, j<c); }
compare('a','b'); compare('a','A');
It seems that console should be outside of the curly braces. I know that compare('a','b'); compares the two arguments but....I think that I am lost in the order of processing.......
Tristan Gaebler
6,204 Pointsconsole.log should be inside the braces. Once the function receives input it heads to the body, which will compare a and b.
Daniel Stepanenko
2,376 PointsI won't quite understand why the ,a<b) portion does a comparison.
Is there something implicate in this syntax?
pgmd
6,897 Pointspgmd
6,897 PointsIn full example: function compare(j,c) { console.log(j+"<"+c, j<c); }
compare('a','b'); compare('a','A');
It seems that console should be outside of the curly braces. I know that compare('a','b'); compares the two arguments but....I think that I am lost in the order of processing.......