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JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

Austin Ward
Austin Ward
2,067 Points

Code won't validate. What am I doing wrong?

Rechecked spelling between parameters and variables and it appears to be good. The only thing I could think to change would be the location of where I call he AJAX request within the Doc.ready function but doubt this will make a difference. I am sure I am missing something obvious.

Thanks!

weather.js
$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  };

  $.getJSON(weatherAPI, data, showWeather(weatherReport));
});
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
</head>
<body>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>
  </div>
</body>
</html>

1 Answer

Kelly von Borstel
Kelly von Borstel
28,880 Points

Hi, Austin. I don't think you need to pass an argument to the showWeather function.

$.getJSON(weatherAPI, data, showWeather);
Austin Ward
Austin Ward
2,067 Points

Awesome, thank you Kelly!