JavaScript AJAX Basics (retiring) AJAX Concepts A Simple AJAX Example

MICHAEL COOK
MICHAEL COOK
7,248 Points

Codes not working

I've followed along the video and i've read through some of the questions already asked, but for some reason i can't get the code to work. I'm working on it through SublimeText and accessing it through my local server but nothing is coming up, can anyone help?

this is the code I have:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <link href='//fonts.googleapis.com/css?family=Varela+Round' rel='stylesheet' type='text/css'>
  <link rel="stylesheet" href="css/main.css">
  <title>AJAX with JavaScript</title>
  <script>
 var xhr = new XMLHttpRequest();
 xhr.onreadystatechange = function () {
  if (xhr.readyState === 4) {
    document.getElementByID('ajax').innerHTML = xhr.responseText;
  }
 };
 xhr.open('GET', 'sidebar.html');
 xhr.send();
  </script>
</head>
<body>
  <div class="grid-container centered">
    <div class="grid-100">
      <div class="contained">
        <div class="grid-100">
          <div class="heading">
            <h1>Bring on the AJAX</h1>
          </div>
          <div id="ajax">

          </div>
        </div>
      </div>
    </div>
  </div>
</body>
</html>

1 Answer

Hakim Rachidi
Hakim Rachidi
32,051 Points

Hi Michael,

You ' ve made a small mistake. The line in the callback where you get the the response text and tried to put it into the ajax div you misspelled the function name:

document.getElementbyID( ... );
// instead of
document.getElementbyId( ... );

Hope this helps;