Coding challenge: try and except.

Question

Any insight as to why this doesn't work would be greatly appreciated!
```
def add (win, lose):
try:
    count = int(input("Enter a number: "))
except ValueError:
    return None
else:
    return (float(win)+float(lose))
```
Thank you!

Kevin Faust · Accepted Answer

We dont take in a user input. The numbers will be passed in for us automatically
```python
def add (win, lose):
  try:
    win = float(win)
    lose = float(lose)
  except ValueError:
    return None
  else:
    return win+lose
```
So in your try block, you want to see if you can convert the passed in numbers to floats. If you can, then the rest of the try block will run and the float values will be reassigned to the variable, then we return it. Otherwise we return None
What you did also works. This would work as well:
```python
def add (win, lose):
  try:
    float(win)
    float(lose)
  except ValueError:
    return None
  else:
    return (float(win)+float(lose))
```
We dont reassign the variables passed in but rather we just check if any error will be thrown in our try block and then we do the converting in our else statement

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Drew Rollins

Drew Rollins

Coding challenge: try and except.

1 Answer

Kevin Faust

Kevin Faust

Drew Rollins

Drew Rollins