Combo

Start with a new empty list inside your function, then use a for loop to iterate through the arguments (remember, the challenge says both arguments will be the same length, so iterating over either one works), then on each pass in the loop append a single tuple with the current index's value from both argument one, and argument two to your previously empty list. Last, return your created list. I hope this helps!

Read the problem more carefully:

Create a function named combo that takes two ordered iterables. These could be tuples, lists, strings, whatever.

Your function should return a list of tuples. Each tuple should hold the first item in each iterable, then the second set, then the third, and so on. Assume the iterables will be the same length.

Check the code below for an example.

• The first line ("Create a function named combo ...") says that your function takes two iterables. An iterable can be a string, a tuple, a list, etc.
  
• The second line says that your function should return a list of tuples. Each tuple in the list holds the first value in the first iterable and the first value in the second iterable, the second value in the first iterable and the second value in the second iterable, etc. For example:

combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]

As you can see, the first tuple in the returned list contained the first values of each of the iterables, the second tuple hold the values of the second values in each iterable, etc.

Here's a working solution:

def combo(iter1, iter2):
    result = []
    for i in range(len(iter1)):
        result.append((iter1[i], iter2[i]))
    return result

The solution is simple:

1. We make a function that takes two arguments: iter1 and iter2.
2. We set up the result list.
3. We make a for loop. The variable i keeps track of the index.
4. We extract the values from the two iterables using the index then append it to result.
5. We return result.

Does this clear things up?

I hope this helps!

Happy coding! ~Alex