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Brittany Allen
9,803 PointsCombo Tuple Challenge
I've been working at the combo challenge for quite a while and I feel like I'm close, but I still don't quite have it. I get the error message "Got [(1, 'T'), (2, 'r')], expected [(1, 'T'), (2, 'r'), (3, 'e'), (4, 'e'), (5, 'h'), (6, 'o'), (7, 'u'), (8, 's'), (9, 'e')]".
Here is the link to the challenge
def combo(iterable1, iterable2):
combo_list = []
a = []
b = []
index = 0
for item in iterable1:
a.append(item)
for item in iterable2:
b.append(item)
for item in a, b:
c = a[index], b[index]
combo_list.append(c)
del c
index += 1
return combo_list
4 Answers
Juan Martin
14,335 PointsHello friend, let me show you what I did, it was with 1 variable and 1 loop. Hope this helps :)
def combo(iterable1,iterable2):
tuple_list= []
for idx in range(len(iterable1)):
tuple_list.append((iterable1[idx],iterable2[idx]))
return tuple_list
Kenneth Love
Treehouse Guest TeacherThis is also a great challenge to use enumerate() on. It should save you a lookup.
Chris Saden
8,652 PointsThere's also a handy function called zip(). Try running zip([1, 2, 3], ['a', 'b', 'c']) or look up the documentation for zip.
[MOD: fixed formatting]
Kenneth Love
Treehouse Guest TeacherAww, don't make it easy! :)
But, yes, zip() does exist and I did just make you build it yourself.
Trust Mujaka
1,821 PointsMy solution using the enumerate method.
def combo (itr1, itr2): tuple_list = [] for index, value in enumerate (itr1): tuple_list.append((value, itr2[index])) return tuplelist
Brittany Allen
9,803 PointsBrittany Allen
9,803 PointsThank you so much! I knew I must have been making it too complicated.
Juan Martin
14,335 PointsJuan Martin
14,335 PointsYou're welcome :) I'm glad I could help you
Taig Mac Carthy
8,139 PointsTaig Mac Carthy
8,139 PointsYou da best