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Java

Ian Hawe
PLUS
Ian Hawe
Courses Plus Student 10,579 Points
Posted by Ian Hawe
Ian Hawe
Courses Plus Student 10,579 Points

Comparing an array to itself to get distinct values using Java

public static void main(String[] args) { int[] data = {81, 81, 4, 1, 1, 2, 3, 81, 4, 5, 6, 7, 8, 9, 10, 10, 12, 1, 81}; findDistinctElements(data); }

public static void findDistinctElements(int[] data) {
    for (int i = 0; i < data.length; i++) {
        boolean distinct = true;
        for (int j = 0; j < i; j++) {
            if (data[i] == data[j]) {
                distinct = false;
                break;
            }
        }
        if (distinct) {
            System.out.print(data[i] + " ");
            //81,4,1,2,3,5,6,7,8,9,10,12 = Distinct numbers
        }
    }
}

Are there any other methods to do this? or more easier to read methods? perhaps performance increasing?

1 Answer

Manish Giri
Manish Giri
16,266 Points
Manish Giri
Manish Giri
16,266 Points

You can create a HashSet from the array, which will contain only the distinct values in the array.