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JavaScript JavaScript Foundations Strings Comparing Strings

Posted by Clifford Fajardo
Clifford Fajardo
13,127 Points

Comparing Strings

After watching the "Comparing Strings" video I decided to test out some code for learning purposes, but I need help.

In the video at 5:10 / 9:48 Jim went over this first function below:

function compare(a, b) {
    console.log(a + ' < ' + b,  a < b)
}

compare('a', 'b');

This prints in the console: a < b true

Ok easy.

But why do I get: Uncaught SyntaxError: Unexpected Number

When I try this function out?

function comparison(1, 2) {
    console.log(1 + ' < ' + 2, 1 < 2)
}

comparison('1', '2')

Could it be that I am getting the syntax errors because I am using numbers in my argument ( i.e. (1,2) )?

2 Answers

Purvi Agrawal
Purvi Agrawal
7,960 Points
Purvi Agrawal
Purvi Agrawal
7,960 Points

Yes, using numbers in function definition can be the mistake. Generally, we use variables in function definition and numbers or values in function call. Try using variables in function definition i.e. function comparison(a, b) . Also, u can directly pass numbers as comparison(1, 2) instead of comparison('1', '2'). The one u used is converting numbers into string as enclosed in single quotes. Hope it would be helpful.

Clifford Fajardo
Clifford Fajardo
13,127 Points
Clifford Fajardo
Clifford Fajardo
13,127 Points 
function comparison(a, b) {
    console.log(a + ' < ' + b, a < b);
}

comparison(1, 2);

I tried this method and it worked. Problem solved, thanks Purvi Agrawal !