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Raymond Carter, Jr.
iOS Development Techdegree Student 488 Pointscompletely lost in this code challenge
For this challenge, we'd like to know in a range of values from 1 to 100, how many numbers are both odd, and a multiple of 7.
To start us off, I've written a for loop to iterate over the desired range of values and named the local constant n. Your job is to write an if statement inside the for loop to carry out the desired checks.
If the number is both an odd number and a multiple of 7, append the value to the results array provided.
Hint: To check for an odd number use the not operator to check for "not even"
Can somebody give me a step by step breakdown in how to do this, please?!
var results: [Int] = []
for n in 1...100 {
// End code
}
2 Answers
Mathieu St-Vincent
9,244 PointsIt can be encapsulated in a single if
var results: [Int] = []
for n in 1...100 {
if(n % 7 == 0 && n % 2 != 0) {
results.append(n)
}
// End code
}
By using the modulo, we can find the remainder after the division of one number to another.
IF the remainder of dividing n with 7 equals 0, it means it is a multiple of 7
AND if the remainder of dividing n with 2 doesn't equal (!=) 0, it means the number is not even, so it is odd.
With all conditions met in the single IF means it is true, so we can append(n) to the results array.
Raymond Carter, Jr.
iOS Development Techdegree Student 488 Pointstwo questions... How did you know to divide it by 0 and that you needed to use the remainder operator to solve this problem? Can you go into a little more detail for more its still not clicking for me