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951 Pointsconditional around the final echo command that checks if the variable has a value of "cookie dough"
The message in the final echo command only makes sense if your favorite flavor is the same as Hal's.Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough."(Remember to choose carefully between using a equal sign and a double equal sign in the check.Preview code and if u have different flavor, make sure the message disapears.
<?php
$flavor='vanilla';
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor='vanilla';
echo ".</p>";
echo "<p>Hal's favorite flavor is cookie dough, also!</p>";
echo .Hal.$flavor='cookie dough,also!';
if($flavor=='.Hal.$flavor,also!';){
]
?>
1 Answer
Simon Coates
28,694 Pointsthe correct code is
<?php
$flavor = "Strawberry";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if($flavor == "cookie dough"){
echo "<p>Hal's favorite flavor is cookie dough, also!</p>";
}
?>