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Python

Posted by Brandon Wall
Brandon Wall
5,512 Points

Conditional if statement using a type e.g. if x == int: Help please.

I'm re-creating the number game completely from scratch without looking at any videos and trying my best to only use python's help function. I want to create an if statement like this

if our_num == int:
    break

#So far i'm having to settle for this

if our_num >= 0:
break

This is for a while loop with a try and except block basically letting them choose the difficulty of the game. If they don't enter an int, I have the computer give an angry message saying basically ' don't mess with me, enter a real number' and then loop back to the message prompting them to choose difficulty but i want the break to function based on whether or not the difficulty variable is successfully casted to an int type.

2 Answers

Jeffrey Ruder
Jeffrey Ruder
6,408 Points

Another way to do this is:

if isinstance(a, int):
  #do stuff
Brandon Wall
Brandon Wall
5,512 Points

Awesome, I like that way too. I shall experiment with it. Thank you :D

Brandon Wall
Brandon Wall
5,512 Points
Brandon Wall
Brandon Wall
5,512 Points

I actually just figured it out: <br> <br> <br>

a = 4 
while True:
    print("Hello World")
    if type(a) == int:
        break

<br> <br> Oh god i'm so bad at this formatting thing, sorry this is my first post.

Didn't want to create a new post to play around with formatting stuff, so I'm just editing my post here and playing around with markdown syntax. :P don't mind me.